The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by of the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Accepted Solution
A:
Let T denote temperature, °F
At 5:00 a.m.: T = -6 °F
At 3:00 p.m.: T = 36 °F The rise in temperature from 5:00 am is 36 - (-6) = 42 °F
At 8:00 p.m.: The temperature decreased from the high of 36 °F by 42 °F (equal to the amount of increase from 5:00 a.m. to 3:00 p.m.). Therefore the temperature at 8:00 p.m. is 36 - 42 = -6 °F