A coordinate plane with a line drawn passing through the points (0, 3) and (3, 2).Which equation represents the graphed function?y = –3x + 3y = 3x – 3y = 3x – negative StartFraction 1 Over 3 EndFraction.y = –x + 3

Answer:None of the equations given is the equation of the function. The correct equation is: [tex] y=-\frac{x}{3}+3\\[/tex]Step-by-step explanation:First we must find the slope of the line that passes through these points.The slope between two points [tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] is given by:[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]where [tex]m[/tex] is the slopeIn this case since we have the points: [tex](0, 3)[/tex] and [tex](3, 2).[/tex][tex]x_{1}=0\\y_{1}=3\\x_{2}=3\\y_{2}=2[/tex]and the slope will be:[tex]m=\frac{2-3}{3-0}=\frac{-1}{3}[/tex]and now we have the slope we use the slope-point equation:[tex]y=m(x-x_{1})+y_{1}[/tex][tex]y=-\frac{1}{3}(x-0)+3\\ y=-\frac{x}{3}+3\\[/tex]